+13 Saquina dilates a digital photograph by a factor of 1.75 to create a new digital photograph similar to her original photograph.
Select from the drop-menus to correctly complete the statement.
The perimeter of Saquina's new photograph is [Choose] times larger than the perimeter of her original photograph, and the area of her new photograph is [Choose.] times larger than the area of her original photograph.
First choose options are
1.75
7
3.0625
3
3.5
The second Choose options are the same
1.75
7
3.0625
3
3.5
+9481 Here's how I like to think of these...
original perimeter = 2(L + W)
To scale the photo, mulitply the length by 1.75 and the width by 1.75 , so that
the new length = 1.75L and the new width = 1.75W
new perimeter = 2(1.75L + 1.75W)
new perimeter = 1.75 * 2(L + W)
new perimeter = 1.75 * original perimeter
new perimiter is 1.75 times the original perimeter
original area = L * W
new area = 1.75L * 1.75W
new area = 1.75 * 1.75 * L * W
new area = 1.752 * L * W
new area = 1.752 * original area
new area = 3.0625 * original area
new area is 3.0625 times the original area
+9481 Here's how I like to think of these...
original perimeter = 2(L + W)
To scale the photo, mulitply the length by 1.75 and the width by 1.75 , so that
the new length = 1.75L and the new width = 1.75W
new perimeter = 2(1.75L + 1.75W)
new perimeter = 1.75 * 2(L + W)
new perimeter = 1.75 * original perimeter
new perimiter is 1.75 times the original perimeter
original area = L * W
new area = 1.75L * 1.75W
new area = 1.75 * 1.75 * L * W
new area = 1.752 * L * W
new area = 1.752 * original area
new area = 3.0625 * original area
new area is 3.0625 times the original area
