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A team of 10 players is to be selected from a class of 6 girls and 7 boys. . the probability that a randomly chosen team has 3 girls and 7 boys

 Aug 4, 2016
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The total possible teams formed = C(13,10)   = 286

 

Since we have 7 boys and we want to choose 7, they must all be on the team  = C(7, 7)  = 1

 

And the number of different sets of girls that could be chosen = C(6,3)  = 20

 

So.....the probabiity that a team has  7 boys and 3 girls =  [C(7,7) * C(6,3)] / C(13, 10) =    [1 * 20 ] / 286 =  aboiut .0699  or about 7%

 

 

 

cool cool cool

 Aug 4, 2016

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