A team of 10 players is to be selected from a class of 6 girls and 7 boys. . the probability that a randomly chosen team has 3 girls and 7 boys
+129487 The total possible teams formed = C(13,10) = 286
Since we have 7 boys and we want to choose 7, they must all be on the team = C(7, 7) = 1
And the number of different sets of girls that could be chosen = C(6,3) = 20
So.....the probabiity that a team has 7 boys and 3 girls = [C(7,7) * C(6,3)] / C(13, 10) = [1 * 20 ] / 286 = aboiut .0699 or about 7%
