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avatar+3031 

In the diagram, \(K\)\(O\)  and \(M\) are the centers of the three semi-circles. Also, \(OC = 32\)  and \(CB = 36\) .



What is the area of the semi-circle with center \(K\)?

 

tertre  Apr 1, 2018

Best Answer 

 #1
avatar+7266 
+4

OB   =   OC + CB   =   32 + 36   =   68

 

AB   =   2 * OB   =   2 * 68   =   136

 

AC   =   AB - CB   =   136 - 36   =   100

 

diameter of circle K   =  AC  =  100

 

radius of circle K   =  100/2   =   50

 

area of semicircle K   =   (1/2)(pi)(502)   =   1250pi  sq units

hectictar  Apr 2, 2018
 #1
avatar+7266 
+4
Best Answer

OB   =   OC + CB   =   32 + 36   =   68

 

AB   =   2 * OB   =   2 * 68   =   136

 

AC   =   AB - CB   =   136 - 36   =   100

 

diameter of circle K   =  AC  =  100

 

radius of circle K   =  100/2   =   50

 

area of semicircle K   =   (1/2)(pi)(502)   =   1250pi  sq units

hectictar  Apr 2, 2018
 #2
avatar+3031 
+3

Thank you so much, hectictar!

tertre  Apr 2, 2018

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