Geometry help

Once again, this is a basic trigonometry relationship problem. 

In this case, we can use tangent or cotangent. 

Tangent is opposite over adjacent

Cotangent is adjacent over opposite.

Let’s just say we use tangent.

\(\tan{x}=\frac{26}{53}\)

I hope this helped,

Gavin

We know  the oppoite side and the adjacent side....the inverse tangent is what we need

arctan ( 26/53)  = 26.1°