\(In the figure shown, the ratio of $BD$ to $DC$ is $4$ to $3$. The area of $\triangle ABD$ is $24$ square centimeters. What is the area of $\triangle ADC$? \)
Edited by Melody to make it readable:
In the figure shown, the ratio of BD to DC is 4 to 3. The area of triangle ABD is 24 square centimeters.
What is the area of triangle ADC?
pls can someone help
I have been waiting for someone to help me for a long time
Hi Shreyas1,
You most likely would have had an answer much more quickly if your question was presented in a readable fashion!
But here is your answer
\(\frac{BD}{DC}=\frac{4}{3}\\ \text{so let BD=4x and DC=3x }\\ Area\;\;\triangle ABD=0.5*4x*h=24\\ \qquad \qquad 2xh=24\\ \qquad \qquad xh=12\\~\\ Area\;\;\triangle ABC=0.5*7x*h\\ Area\;\;\triangle ABC=3.5xh\\ Area\;\;\triangle ABC=3.5*12\\ Area\;\;\triangle ABC=42cm^2\\\)
NOW do the subtraction to get the final answer :)