\(In the figure shown, the ratio of $BD$ to $DC$ is $4$ to $3$. The area of $\triangle ABD$ is $24$ square centimeters. What is the area of $\triangle ADC$? \)

Edited by Melody to make it readable:

In the figure shown, the ratio of BD to DC is 4 to 3. The area of triangle ABD is 24 square centimeters.

What is the area of triangle ADC?

shreyas1 Oct 1, 2018

#1**0 **

pls can someone help

I have been waiting for someone to help me for a long time

shreyas1 Oct 2, 2018

#2**+1 **

Hi Shreyas1,

You most likely would have had an answer much more quickly if your question was presented in a readable fashion!

But here is your answer

\(\frac{BD}{DC}=\frac{4}{3}\\ \text{so let BD=4x and DC=3x }\\ Area\;\;\triangle ABD=0.5*4x*h=24\\ \qquad \qquad 2xh=24\\ \qquad \qquad xh=12\\~\\ Area\;\;\triangle ABC=0.5*7x*h\\ Area\;\;\triangle ABC=3.5xh\\ Area\;\;\triangle ABC=3.5*12\\ Area\;\;\triangle ABC=42cm^2\\\)

NOW do the subtraction to get the final answer :)

Melody Oct 2, 2018