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I need help with this question please! Thank you. 

 

 Jun 4, 2019
 #1
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Construct a circle of any radius and let chords AB and CD be parallel

Join AD, BC  and let E be the intersection of these chords

Now....because AB and CD are parallel and AD and BC are transversals, then angle BAE = angle CDE 

And angle ABE = angle DCE  for the same reason

And angle ABE = angle CDE  because they intercept the same arc

And angle BAE = angle DCE for the same reason

Therefore....angle CDE = angle DCE...so....in triangle CED.....CE = DE

And....angle BAE = angle ABE....so..in triangle AED.....AE = BE

Therefore....AE + DE  = CE + BE

And....AE + DE = AD

And CE + BE  = BC

So....AD = BC

 

 

 

cool cool cool

 Jun 4, 2019
edited by CPhill  Jun 4, 2019
edited by CPhill  Jun 4, 2019
edited by CPhill  Jun 4, 2019
edited by CPhill  Jun 4, 2019
edited by CPhill  Jun 4, 2019

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