The napkin ring pictured is to be resilvered. How many square millimeters must be covered in terms of pi?
+605 \(2\pi r*h=2\pi *5*2=20\pi\). Now for top and bottom. Top is \(5^2\pi-2^2\pi=25\pi-4\pi=21\pi\), and so is bottom. So ans is \(20\pi+21\pi+21\pi=\boxed{62\pi}\).
