Find the area of each triangle to the nearest tenth.
First one
sin F / 5 = sin 35 / 9
sin F = 5 sin 35 /9
arcsin ( 5 sin 35 / 9) = F ≈ 18.58°
Angle E =180 - 35 -18.58 = 126.42°
Area = (1/2) (5 * 9) sin 126.42 ≈ 18.1 cm^2
Second one
Angle E = 180 - 50 - 66 = 64°
Law of Sines :
8 / sin 64° = EF /sin 50°
EF = 8 sin 50° / sin 64 ° = 6.8
Area = (1/2) ( 6.8 * 8) sin 66° = 24.8 cm^2
