Geometry - Perpendicular Lines

In the equation:  y  =  mx + b                             m  is the slope   and   b  is the y-intercept.

 

y  =  (3x/2) - 5     --->     y  =  (3/2)x - 5           (3/2)  is the slope   and   -5  is the y=intercept

 

Any line parallel to this line has a slope of  3/2     and

any line perpendicular to this line has a slope of -2/3.

 

So any line perpendicular to  y  =  (3/2)x - 5     has this form:     y  =  (-2/3)x + b

 

Now, take any five different values for b; for instance,  y  =  (-2/3)x + 17   and   y  =  (-2/3)x - 247,  

etc.