+0  
 
0
34
1
avatar

If MN=NQ and MQ=QR=RP, calculate for x​

 

 Mar 28, 2021
 #1
avatar+136 
0

\(MQ=QR=RP\)

\(\angle QMR=\angle QRM=x\)

\(\angle MQR=180-2x\)

\(\angle RQP=\angle RPQ=180-(180-2x)=2x\)

\(\angle QRP=180-2x- 2x=180-4x\)

\(\angle MRN=180-(180-4x)-x=3x\)

because \(\angle NMR=\angle NRM \) we know that \(MN=NR\)

\(MN=NQ=NR\)

\(\angle NMQ=\angle NQM=\angle NRQ=\angle NQR=4x\)

\(\angle MQN+\angle NQR+\angle RQP=180\)

\(4x+4x+2x=180\)

\(x=18\) (C)

 Mar 28, 2021

85 Online Users

avatar
avatar
avatar
avatar
avatar
avatar