+0  
 
0
87
1
avatar

In triangle ABC we have that AB=AC=14 and BC=20. What is the length of the shortest angle bisector in ABC? Express your answer in simplest radical form.

 May 28, 2021
 #1
avatar+121047 
+1

This  triangle  is  isosceles....the  shortest  angle  bisector  is  that of  angle BAC  =

 

sqrt [ AC^2  -  (BC/2)^2  ]  =

 

sqrt [  14^2  - 10^2 ]  =

 

sqrt  96  =

 

4 sqrt 6

 

 

cool cool cool

 May 28, 2021

26 Online Users

avatar