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In triangle JKL, we have JK = JL = 25 and KL = 20. Find the circumradius

 Aug 25, 2021
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Find the circumradius.

 

Hello Guest!

 

Cosine law:

cos(α)=b2+c2a22bc=225220222525=0,68α=acos(0,68)=47.156°α2=23.578°

cos(α2)=252rr=12.5cos(23.578°)=13.639

The circumradius is r=13.639.

laugh  !

 Aug 25, 2021

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