Triangle ABC is equilateral. Find x.
sqrt 3 / 2 * AB = sqrt 3 / 2 * 8 = 4 sqrt 3
Since it is equilateral, then AD bisects CB, so CD = 4. Using the pythagorean theorem, AD is 8^2 - 4^2 = AD^2
So AD = \(4\sqrt{3}\)
+36915 
