The line joining (3,2) and (6,0) divides the square shown into two parts. What fraction of the area of the square is above this line? Express your answer as a common fraction.
See the following image :
The area of the square = 3*3 = 9 units^2
The area BELOW the line is a triangle with base 3 and height 2 ....so its area = (1/2)(3)(2) = 3 units^2
So....the area ABOVE the line must be 9 - 3 = 6 units^2
So....this area is 6/9 = 2/3 of the area of the square
The square is 3 x 3 = 9 sq units
The line draws a triangle height 2 base 3 area = 1/2 bh = 1/2 (2)(3) = 3 sq units
9 - 3 = 6 sq units above line or 6/9 or 2/3 above the line