EFGH is a rectangle with area 48. If EGJI is a rectangle such that H is on JI, what is the area of EGJI?
We know that the area of a rectangle is the length times the width. Since the area of EFGH is 48 and the width is 12, the length of EFGH is 4.
Therefore the area of EGJI is 2⋅4=8. So the answer is 8