geometry problem

In a quadrilateral ABCD , AB || DC . If angle A : angle D = 2:3 and angle B : angle C = 7:8 , find the measure of each angle​

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$\alpha :(180^{\circ} -\alpha )=2:3\\ 3\alpha =360^{\circ} -2\alpha\\ 5\alpha=360^{\circ}$

$\alpha =72^{\circ}$

$\beta:(180^{\circ} -\beta)=7:8\\ 8\beta=1440^{\circ} -7\beta\\ 15\beta=1440^{\circ}$

$\beta=96^{\circ}$

$\gamma=180^{\circ} -\beta=180^{\circ} -96^{\circ}$

$\gamma=84^{\circ}$

$\delta=180^{\circ} -\alpha=180^{\circ} -72^{\circ}$

$\delta=108^{\circ}$

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