+92 Prove that in an isoceles triangle two of the medians (the lines drawn from the vertex to the midpoint of the opposite side) are congruent.
+129852 Let ABC be an isosceles triangle with AB = AC
Draw median BM to side AC and median CN to side AB
Note that since AB = AC...then then the medians divide AB and AC into two equal parts.....so....MC = NB
And since AB = AC, then angle ABC = angle ACB
And BC = BC
So...by side-angle side.....triangle MCB is congruent to triangle NBC
So...therefore....BM = CN
See this image :
