geometry question

How many grams of Mg are in a 110g sample of Mg(CN)2?

\(1 \ Mol \ von \ Mg(CN)_2 =(24.305+2(12.011+14.007)g= 76.341g\)

                                                     Mg                  C                     N             

\(x : 24.305g\ Mg=110g \ Mg(CN)_2 : 1Mol \ Mg(CN)_2 \)

\(x : 24.305g\ Mg=110g \ Mg(CN)_2 : 76.341g \ Mg(CN)_2 \)

\(\large x=\frac{24.305g\ Mg\times 110g \ Mg(CN)_2}{76.341g \ Mg(CN)_2 }\)

\(x=35.021g \ Mg\)

In 110g Mg(CN)₂   35.021g Mg are contained.

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