The vertex of the right isosceles triangle is the center of the square. Each leg of the right isoscles triangle is 6. What is the area of the overlapping region?
Each smaller triangle is similar to the larger isosceles right triangle
Each leg of these two triangles = (6 - 5) =1 unit
So.....their combined areas = 2 (1/2) (1) ( 1) = 1
Area of isosceles triangle = (1/2) (6)(6) =18
Area of overlap = 18 - 1 = 17 units^2
