The lengths of two sides of a triangle are 33 units and 42 units. The third side also has an integral length. What is the least possible number of units in the perimeter of the triangle?

Guest Jun 27, 2018

By the triangle inequality  we have that


S  + 33 > 42     where S is the shortest side


Subtract 33 from each side


S  >  9  units


So...since the shortest side has an integer length.....this length must be  10 units


So....the least perimeter  is    10  + 33 + 42   =   85 units



cool cool cool

CPhill  Jun 27, 2018

11 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.