A right triangle has legs of length 6 and b and a hypotenuse of length c . The perimeter of the triangle is 12. Compute c.
\(6+b+c=12\\ c=6-b\\~\\ 6^2+b^2 = c^2\\ 36+b^2=(6-b)^2 \)
You are WRONG!!!! You deleted my answer because I was right!!!
The question is wrong!!! Neither leg of this triangle can be 6 because the perimeter is 12 and the hypotenuse must be greater than 6.
36 + b2 = (6 - b)2 b = 0 (This is your hint answer.)
I was not wrong.
The first line of your answer was exactly the same as the last line in mine.
I gave an unfinished answer because I do not want this to be primarily a cheat site.
If the student needs more help then they are welcome to ask for it by continuing with the thread.
It is great when students interact with us.
If you want to give complete answers on questions that other people have not already tried to use as a teaching thread.
That is entirely your prerogative.
But please do not answer directly over the top of my teaching / hint answers. (unless I really am wrong)