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A right triangle has legs of length 6 and b and a hypotenuse of length c . The perimeter of the triangle is 12. Compute c.

 Nov 15, 2021
 #4
avatar+115391 
+1

 


\(6+b+c=12\\ c=6-b\\~\\ 6^2+b^2 = c^2\\ 36+b^2=(6-b)^2 \)

 

etc

 Nov 15, 2021
 #6
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You are WRONG!!!! You deleted my answer because I was right!!! 

 

The question is wrong!!!   Neither leg of this triangle can be 6 because the perimeter is 12 and the hypotenuse must be greater than 6.

 

36 + b2 = (6 - b)2        b = 0         (This is your hint answer.) cheeky

 

civonamzuk smiley

Guest Nov 16, 2021
edited by Guest  Nov 16, 2021
 #7
avatar+115391 
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I was not wrong. 

The first line of your answer was exactly the same as the last line in mine. 

I gave an unfinished answer because I do not want this to be primarily a cheat site.

If the student needs more help then they are welcome to ask for it by continuing with the thread.

It is great when students interact with us.

 

-------------

 

If you want to give complete answers on questions that other people have not already tried to use as a teaching thread. 

That is entirely your prerogative.

But please do not answer directly over the top of my teaching / hint answers.  (unless I really am wrong)

Melody  Nov 16, 2021
edited by Melody  Nov 16, 2021
 #8
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I think the both of you are right.

Melody's answer would also lead to the same conclusion as Guest made!

Hope this helps if it confused any of you :)

 Nov 24, 2021

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