+0  
 
0
202
3
avatar

In the diagram, ABC ∼ ACD. If AD = 12 and DB = 15, what is AC? I got it wrong on my test and I don't know how to solve it :(

 Nov 30, 2021
 #1
avatar
-1

By Similar Triangles, AC = 12*sqrt(2).

 Nov 30, 2021
 #2
avatar+9405 
+1

Since △ABC ~ △ACD,

 

AC / AD   =   AB / AC

 

AC / AD  =  AB / AC

 

x / 12  =  27 / x

 

x * x / 12   =   27

 

x * x   =   27 * 12

 

x2   =   324

 

x   =   sqrt(324)

 

x   =   18

 Nov 30, 2021
 #3
avatar
0

? / 12 = 27 / ?

 

? = √324

 

? = 18

 Nov 30, 2021

14 Online Users

avatar
avatar