Square A has side lengths each measuring x inches. Square B has side lengths each measuring x inches. What is the ratio of the area of the smaller square to the area of the larger square? Express your answer as a common fraction.
\({x^2 \over x^2} = \color{brown}\boxed{1}\)
Square A area: x^2
Square B area: 4x^2= 16x^2
x/16x^2=1/16
wait.. is the side length of b 4x inches?
oops my bad. man my eyes need better contacts. you are correct mate.
