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Square A has side lengths each measuring x inches. Square B has side lengths each measuring x inches. What is the ratio of the area of the smaller square to the area of the larger square? Express your answer as a common fraction.

 Jul 2, 2022
 #1
avatar+2275 
0

\({x^2 \over x^2} = \color{brown}\boxed{1}\)

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 Jul 2, 2022
 #2
avatar+1105 
+9

Square A area: x^2

 

Square B area: 4x^2= 16x^2

 

x/16x^2=1/16

 Jul 3, 2022
 #3
avatar+2275 
0

wait.. is the side length of b 4x inches?

 Jul 3, 2022
 #4
avatar+1105 
+10

oops my bad. man my eyes need better contacts. you are correct mate.

nerdiest  Jul 4, 2022

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