Point \(P\) is on side \(\overline{AC}\) of triangle \(ABC\) such that \(\angle APB =\angle ABP\), and \(\angle ABC - \angle ACB = 39^\circ\). Find \(\angle PBC\) in degrees.
Please explain, thanks!
Angle PBC = 24 degrees.
No matter what the measure of angle A is, the measure of angle PBC is constant => 19.5º
