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Point \(P\) is on side \(\overline{AC}\) of triangle \(ABC\) such that \(\angle APB =\angle ABP\), and \(\angle ABC - \angle ACB = 39^\circ\). Find \(\angle PBC\) in degrees. 

Please explain, thanks!

 Jul 5, 2020
 #1
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Angle PBC = 24 degrees.

 Jul 6, 2020
 #2
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No matter what the measure of angle A is, the measure of angle PBC is constant => 19.5º   smiley

 

 Jul 7, 2020

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