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Each triangle in this figure is an isosceles right triangle. The length of BD is 2 units. What is the number of units in the area of quadrilateral ABCD? Express your answer in simplest radical form.

 

 Feb 3, 2021
 #1
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Hi Guest

 

Area of DAB

(2/sqrt(2))^2/2 = 1

 

Area of CDB

2^2/2 = 2

 

1 + 2 = 3

 

I hope this helped. :))

=^._.^=

 Feb 3, 2021

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