Each triangle in this figure is an isosceles right triangle. The length of BD is 2 units. What is the number of units in the area of quadrilateral ABCD? Express your answer in simplest radical form.
Hi Guest
Area of DAB
(2/sqrt(2))^2/2 = 1
Area of CDB
2^2/2 = 2
1 + 2 = 3
I hope this helped. :))
=^._.^=
