what are the center and radius of the circle defind by the equation x^2+y^2-6x+4y+4=0
+36916 x^2+y^2-6x+4y+4=0 put into standard circle equation form
x^2 - 6x + y^2 + 4 = - 4 now, complete the square for x and y
(x-3)^2 + ( y+2)^2 = - 4 + 9 + 4
(x-3)2 + ( y+2)2 = 9 center is thus seen as 3, -2 and radius = sqrt 9 = 3
