So I'm trying to find the measure of an interior angle on a triangle using the law of Sines & Law of Cosines. I'm given Triangle ABC and am told to find Angle C. The measure of Angle A is 97 degrees, the measure of Line AB is 9.1 yd, and the measure of line BC is 11 yd. It is not a right angle, and I can't figure out how to solve it. Would someone please try and help? I would be very grateful.

Guest Mar 22, 2012

#1**0 **

In order to find the measure of an interior angle using Sine, Cosine, and Tangent, you must use the inverse (sin ^{-1} cos ^{-1} tan ^{-1}) For this problem you have to use Tan ^{-1} because the measurements they give you are the opposite and adjacent sides in relation to the angle they give you. What your equation should look like at first is this: tanX=11/9.1. You then isolate X and simplify. Your problem should look like this: X=tan ^{-1}(1.2) Then you plug this into your calculater. Hope I was helpful

teamSOHCAHTOA
Mar 22, 2012