In triangle ABC, AB = AC, and angle A is equal to 36 degrees. Point D is on AC so that BD bisects angle ABC.
(a) Prove that BC = BD = AD.
I just need some hints on this part a... I'm feeling a bit stuck.
Past Question: https://web2.0calc.com/questions/help_80380
The link given didn't really give much for a.
Since AB = AC, the angles ABC = ACB = 72°
Bisecting angle ABC means that angle ABD = angle BAD = 36°
Therefore....in triangle ABD......AD = BD
And the thitd angle in this triangle, BDA = 108°
So angle BDC = 180 - 108° = 72°
And angle ACB = DCB = 72°
So.....in triangle BDC, angle DCB = angle BDC
So BD = BC
BC = BD = AD