Jordan has two glasses. One is a hemisphere with radius 2 inches. THe other is a cylinder with base radius 1 1/4 inches. If the cylindrical glass can hold twice as much water as the hemispherical glass, what is the height of the cylindrical glass?
Thank you
+130511 The volume held by the hemisphere is
(2/3)pi*(2 in)^3 = (16/3) pi in^3
And the cylinder holds twice as much, so....
(32/3)*pi in^3 = pi * (1.25 in)^2 * h where h is the height ... divide both sides by pi
(32/3) in^3 = 1.5625 in^2 * h solve for h
Height of cylinder = (32/3) in^3 / 1.5625 in^2 = about 6.826 in
+130511 The volume held by the hemisphere is
(2/3)pi*(2 in)^3 = (16/3) pi in^3
And the cylinder holds twice as much, so....
(32/3)*pi in^3 = pi * (1.25 in)^2 * h where h is the height ... divide both sides by pi
(32/3) in^3 = 1.5625 in^2 * h solve for h
Height of cylinder = (32/3) in^3 / 1.5625 in^2 = about 6.826 in
