The areas of two similar rectangles add up to 39 square units. Twice the area of Rectangle A plus one-third the area of Rectangle B equals 33 square units. What are the areas of Rectangles A and B?
Thank you guys for helping me, math is not my favorite subject…
Call x the area of A and y the area of B
And we know that
x + y = 39
And that
2x + (1/3)y = 33
Using the first equation, we have that y = 39 - x and subbing for y in the second, we have
2x + (1/3)(39 - x) = 33 simplify
2x + 13 - (1/3)x = 33 multiply through by 3 to clear the fraction
6x + 39 - x = 99
5x + 39 = 99 subtract 39 from both sides
5x = 60 divide by 5 on both sides
x = 12 sq units this is the area of A
And 39 - 12 = 27 sq units .... is the area of B
Call x the area of A and y the area of B
And we know that
x + y = 39
And that
2x + (1/3)y = 33
Using the first equation, we have that y = 39 - x and subbing for y in the second, we have
2x + (1/3)(39 - x) = 33 simplify
2x + 13 - (1/3)x = 33 multiply through by 3 to clear the fraction
6x + 39 - x = 99
5x + 39 = 99 subtract 39 from both sides
5x = 60 divide by 5 on both sides
x = 12 sq units this is the area of A
And 39 - 12 = 27 sq units .... is the area of B