+77 By how many degrees does the measure of an interior angle of a regular octagon exceed the measure of an interior angle of a regular hexagon?
+129933
Interoir angle of a regular polygon = [ n - 2 ] *180 / n where n is the number of sides
Octagon = [8 - 2 ] * 180 / 8 = 3/4 * 180 = 135°
Hexagon = [ 6 - 2 ]* 180 / 6 = (2/3) * 180 = 120 °
So....the interior angle of a regular octagon exceeeds that of a regular hexagon by 15°
