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In trapezoid $EFGH,$ $\overline{EF} \parallel \overline{GH},$ and $P$ is the point on $\overline{EH}$ such that $EP:PH = 1:2$.  If the area of triangle $EF = 3$ and $HG = 10$, and the height of the trapezoid is $6$, then find the area of triangle $PFG$.

 
 Mar 9, 2024

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