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Find the total surface area and the volume of the conical frustum below.

 

 Jul 20, 2024
 #1
avatar+1950 
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Let's make some obersvations. We have that
L=922+(3325)2=922+82=4533R=33r=25


Surface area = πL(R+r)+π(R2+r2)=π[4533](58)+π(332+252)22211.49units2


S1=π332S2=π252H=92


Volume  = 

H/3(S1+S2+S1S2)=92/3(π(332+252)+π332π252)244612.78units3

 

Thus, The answer is 244612.78

 

 

Thanks! :)

 Jul 21, 2024
edited by NotThatSmart  Jul 21, 2024

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