Find the total surface area and the volume of the conical frustum below.
Let's make some obersvations. We have that
L=√922+(33−25)2=√922+82=4√533R=33r=25
Surface area = πL(R+r)+π(R2+r2)=π[4√533](58)+π(332+252)≈22211.49units2
S1=π∗332S2=π∗252H=92
Volume =
H/3∗(S1+S2+√S1∗S2)=92/3∗(π(332+252)+√π∗332∗π∗252)≈244612.78units3
Thus, The answer is 244612.78
Thanks! :)