Geometry

Let's make some obersvations. We have that
\(L =   \sqrt {92^2  + (33-25)^2} =   \sqrt{ 92^2 + 8^2} =  4\sqrt {533} \\ R = 33 \\ r =25\)

Surface area = \(\pi L (R + r) + \pi (R^2 + r^2)  = \pi [ 4\sqrt{533} ](58) + \pi ( 33^2 + 25^2)  ≈ 22211.49 units^2 \)

\(S1  =  \pi * 33^2    \\       S2  = \pi * 25^2    \\   H  = 92 \)

Volume  = 

\( H/3 * ( S1 + S2 +  \sqrt  { S1 * S2 })  =  \\ 92/3  *  ( \pi (33^2 + 25^2) +  \sqrt{\pi*33^2 * \pi* 25^2} ) ≈ 244612.78 units^3\)

Thus, The answer is \( 244612.78\)

Thanks! :)