A pyramid with volume 40 cubic inches has a rectangular base. If the length of the base is doubled, the width tripled and the height increased by 60%, what is the volume of the new pyramid, in cubic inches?
+36916 Rectangular pyramid volume = 1/3 L W H
Now change the L W H
1/3 ( 2L)(3W)(1.6H) =( 9.6 ) * 1/3 L W H
So the original volume is increased by factor of 9.6 9.6 * 40 = 384 in3
+36916 Rectangular pyramid volume = 1/3 L W H
Now change the L W H
1/3 ( 2L)(3W)(1.6H) =( 9.6 ) * 1/3 L W H
So the original volume is increased by factor of 9.6 9.6 * 40 = 384 in3
