In the figure below, ABDC, EFHG, and ASHY are all squares; and AB = EF = 1 and AY = 6. What is the area of quadrilateral DYES?
+128448 AC = AB = 1
CY = AY - AC = 6 - 1 = 5
Area of square ASHY = (AC + CY)^2 = (1 + 5)^2 = 6^2 = 36
Area of 2 smaller squares = 2 (1)^2 = 2
Triangles CDY, YEG, EFS and SDB are congruent,,,,each has a base of 5 and a height of 1
So....their combined area = 4 (1/2) (5) (1) = 10
Area of DYES =
36 - 2 - 10 = 24
