Let $WXYZ$ be a trapezoid with bases $\overline{XY}$ and $\overline{WZ}$. In this trapezoid, $\angle ZXW = 120^\circ$, $\angle XWZ = 60^\circ$, and $\angle XYZ = 120^\circ$. Find $\angle YXZ$, in degrees.
\(Find\ \angle YXZ, in\ degrees.\)
If angle XWZ = 60°, angle WXY = 180° - 60° = 120° because XY and WZ are parallels.
Angle ZXW must be less than 120°.
The question is not solvable.
!
+635 
!
