+0

# geometry

0
123
1

I  is the incenter of ABC. We have CE = 12, AE = 9, and AB = 15. Find BC.

May 7, 2021

#1
+26213
+1

I is the incenter of ABC. We have CE = 12, AE = 9,
and AB = 15.
Find BC.

$$\begin{array}{|rcll|} \hline \mathbf{ \dfrac{BC}{AB} } &=& \mathbf{ \dfrac{CE}{AE} } \\\\ \dfrac{BC}{15} &=& \dfrac{12}{9} \\\\ BC &=& \dfrac{15*12}{9} \\\\ \mathbf{BC} &=& \mathbf{20} \\ \hline \end{array}$$

May 8, 2021