Let ABCD be a trapezoid with bases BC and AD. In this trapezoid, angle DBA = 108, angle ABD = 47, and angle BCD = \(141\). Find angle CBD, in degrees.
\(CBD = 360 - 108 - 47 - 141 = 67 \)
\(\color{brown}\boxed{{\angle}CBD = 67}\)
+2668 
