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Let ABCD be a trapezoid with bases BC and AD. In this trapezoid, angle DBA = 108, angle ABD = 47, and angle BCD = \(141\). Find angle CBD, in degrees.

 Feb 3, 2022
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\(CBD = 360 - 108 - 47 - 141 = 67 \)

\(\color{brown}\boxed{{\angle}CBD = 67}\)

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 Feb 3, 2022

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