+0  
 
0
56
1
avatar

Let ABCD be a trapezoid with bases BC and AD. In this trapezoid, angle DBA = 108, angle ABD = 47, and angle BCD = \(141\). Find angle CBD, in degrees.

 Feb 3, 2022
 #1
avatar+1365 
+2

\(CBD = 360 - 108 - 47 - 141 = 67 \)

\(\color{brown}\boxed{{\angle}CBD = 67}\)

.
 Feb 3, 2022

20 Online Users

avatar