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avatar+1633 

In the diagram below, we have $AB = 24$ and $\angle ADB =90^\circ$. If $\sin A = \frac13$ and $\sin C = \frac12$, then what is $BC$?

 

 

 
 Feb 4, 2025
 #1
avatar+130313 
+1

sin A = 1/3 =  BD/ AB  = BD / 24  →  BD =  8

 

sin C =  1/2 =  BD / BC  = 8 / BC →  BC =  16

 

 

 cool cool cool

 Feb 5, 2025

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