In the diagram below, we have $AB = 24$ and $\angle ADB =90^\circ$. If $\sin A = \frac13$ and $\sin C = \frac12$, then what is $BC$?
sin A = 1/3 = BD/ AB = BD / 24 → BD = 8
sin C = 1/2 = BD / BC = 8 / BC → BC = 16
+1832 
