+1877 In triangle ABC, angle ACB = 90 degrees. Let H be the foot of the altitude from C to side AB.
If BC = 1 and AH = 2, find CH.
+1786 https://web2.0calc.com/questions/right-triangle_44
The length of CH is \( \sqrt {2\sqrt 2 - 2} = \sqrt{\sqrt 8 - 2} ≈ .91 \)
