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Mr. Lomas has a golf poster that is 10 inches longer than it is wide. It is mounted in an exquisite artificial plastic frame with a uniform width of two inches. If the area of the frame is 224 square inches, what is the length of his poster?

 Mar 19, 2021
 #1
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Let  the  width of  the poster  =  W

Let  the length  =  W + 10

 

We  have  that

 

( W + 4 )  ( W + 10 + 4)  =  224    simplify

 

(W + 4)  ( W + 14)  = 224

 

W^2  + 18W + 56  = 224

 

W^2  + 18W  - 168  =  0    complete  the square

 

W^2  + 18W  +  81   =   168  +  81

 

(W  + 9(^2   =   249          take  the  positive root

 

W + 9  = sqrt (249)

 

W  = sqrt  (249)  - 9 

 

L=  sqrt (249) - 9 + 10  =   sqrt (249) +  1 ≈  16.8 in

 

 

cool cool cool                

 Mar 19, 2021

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