The area of a trapezoid is $80$. The length of one base is $16$ units greater than the other base, and one base of the trapezoid is $12$. Find the length of the median of the trapezoid.
Let's note that median of the trapezoid is the average of the two bases.
12 has to be smaller base, since it's impossible to have negative sidelengths.
Thus, we can write the equation
\(\frac{12+(12+16)}{2}=40/2 = 20\)
So our answer is 20.
Thanks! :)
Let's note that median of the trapezoid is the average of the two bases.
12 has to be smaller base, since it's impossible to have negative sidelengths.
Thus, we can write the equation
\(\frac{12+(12+16)}{2}=40/2 = 20\)
So our answer is 20.
Thanks! :)