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# geometry

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what is the equation of a line that is  perpendicular to y=4x+5 through the point (8,3)?

Dec 16, 2021

#1
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Equation of a line that is  perpendicular to y=4x+5 through the point (8,3).

Hello Guest!

$$y=4x+5$$

$$slope = 4\\ m=- \frac{1}{slope}=-\frac{1}{4}$$

Point-direction equation:

$$y=m(x-x_P)+y_P\\ y=-0.25(x-8)+3$$

$$y=-0.25x+5$$

!

Dec 16, 2021