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what is the equation of a line that is  perpendicular to y=4x+5 through the point (8,3)?

 Dec 16, 2021
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Equation of a line that is  perpendicular to y=4x+5 through the point (8,3).

 

Hello Guest!

 

\(y=4x+5\)

\(slope = 4\\ m=- \frac{1}{slope}=-\frac{1}{4}\)

Point-direction equation:

\(y=m(x-x_P)+y_P\\ y=-0.25(x-8)+3\)

\(y=-0.25x+5\)

laugh  !

 Dec 16, 2021

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