what is the equation of a line that is perpendicular to y=4x+5 through the point (8,3)?
Equation of a line that is perpendicular to y=4x+5 through the point (8,3).
Hello Guest!
\(y=4x+5\)
\(slope = 4\\ m=- \frac{1}{slope}=-\frac{1}{4}\)
Point-direction equation:
\(y=m(x-x_P)+y_P\\ y=-0.25(x-8)+3\)
\(y=-0.25x+5\)
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