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Let XY  be a tangent to a circle, and let XBA be a secant of the circle, as shown below. If AX = 16  and XY = 9, then what is AB?

 

 Jun 21, 2022
 #1
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By the tangent - secant theorem

 

XY^2 =  AX * XB

 

9^2  =  16 * XB

 

81  = 16 * XB

 

81 / 16  = XB

 

So

 

BA =  AX - XB 

 

BA  = 16 - 81/16

 

BA =  (256 - 81) / 16

 

BA =  175 / 16

 

 

 

cool cool cool

 Jun 21, 2022

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