Chords UV, WX, and YZ of a circle are parallel. The distance between chords UV and WX is 1, and the distance between chords WX and YZ is also 1. If UV =6 and YZ = 4, then find WX.
Find WX.
hyz=√r2−22huv=√r2−32hyz−huv=2√r2−22−√r2−32=2r=√1454=3.0104 (WolframAlpha)
hyz=2.25huv=0.2500hwx=(2.25+0.250)/2=1.25¯WX=2√r2−h2wx=2√3.01042−1.252¯WX=5.4772
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+2729 
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