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In the diagram, $ABCD$ is a square. Find $PR.$

 



The side length of the square is 10. L, M, N, O are midpoints.

 Mar 15, 2024

Best Answer 

 #1
avatar+34 
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Start out by drawing out your answer on graph paper.

 

Point A is at (0,0), Point B is at (10,0), Point C is at (10,10) Point D is at (0,10).

 

Then you can draw each of the lines. The equations for each of the lines are: DL: y = -2x + 10, NB: y = -2x + 20, OC: y = 1/2x + 5, and AM: y = 1/2x. 

 

After drawing out all of the lines, you can find that Point R is at (6,8) and point P is at (4,2).

 

Use the distance formula or pythag to find the length between the two points.

\(\sqrt{2^2+6^2}=\sqrt{40}=2\sqrt10\)

 

Answer: \(2\sqrt10\)

 Mar 15, 2024
 #1
avatar+34 
+1
Best Answer

Start out by drawing out your answer on graph paper.

 

Point A is at (0,0), Point B is at (10,0), Point C is at (10,10) Point D is at (0,10).

 

Then you can draw each of the lines. The equations for each of the lines are: DL: y = -2x + 10, NB: y = -2x + 20, OC: y = 1/2x + 5, and AM: y = 1/2x. 

 

After drawing out all of the lines, you can find that Point R is at (6,8) and point P is at (4,2).

 

Use the distance formula or pythag to find the length between the two points.

\(\sqrt{2^2+6^2}=\sqrt{40}=2\sqrt10\)

 

Answer: \(2\sqrt10\)

jilin73 Mar 15, 2024

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