In triangle ABC, CA=4sqrt(2), CB=4sqrt(5), and A=60 degrees. What is B in degrees?
+14995 In triangle ABC, CA=4sqrt(2), CB=4sqrt(5), and A=60 degrees. What is B in degrees?
Hello Guest!
Sine law
\(\frac{sin\ \alpha}{4\sqrt{5}}=\frac{sin\ \beta}{4\sqrt{2} }\\ sin\ \beta=\frac{0.5\cdot 4\cdot \sqrt{2}}{4\cdot \sqrt{5}}=\sqrt{\frac{2}{5\cdot4}}=\sqrt{0.1}\\ \)
\(\beta=18.435°\)
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