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Find sin \angle ABC.

 

 Jan 1, 2024
 #1
avatar+129850 
+1

Law of Cosines

 

5^2 = 4^2 + 7^2 - 2(4 * 7) cos (ABC)

 

[5^2 - 4^2 - 7^2 ] / [-2 (4 * 7]  = cos ABC

 

-40 / -56 = cos ABC  =  5 / 8

 

sin ABC =   sqrt [ 8^2 - 5^2 ] / 8  =   sqrt [39 ] / 8

 

 

cool cool cool

 Jan 1, 2024

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