+1839 Let $WXYZ$ be a trapezoid with bases $\overline{XY}$ and $\overline{WZ}$. In this trapezoid, $\angle ZXW = 90^\circ$, $\angle XWZ = 60^\circ$, and $\angle XYZ = 120^\circ$. Find $\angle XZW$, in degrees.
+1897 First, let's note that XZW will form a triangle
From the problem, we have that
\(\angle ZXW = 90^\circ \\ \angle XWZ = 60^\circ\)
Thus, we can easily find XZW since it's the last angle in the triangle.
So \(\angle XZW = 180 - 90 - 60 = 30^\circ\)
Thanks! :)
