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Let $ABC$ be a triangle. Let $D$ be a point on side $\overline{AC}$ such that line segment $\overline{BD}$ bisects $\angle ABC$. If $\angle A = 30^\circ$, $\angle C = 90^\circ$, and $AC = 12$, then find the area of triangle $ABD$. Give your answer in exact form, using radicals as necessary.

 Jun 10, 2024
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The area of triangle ABD is 20*sqrt(2).

 Jun 25, 2024

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